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120012122219989 is a prime number
BaseRepresentation
bin11011010010011001111111…
…111010011110010111010101
3120201221001021010212121121011
4123102121333322132113111
5111212234311242014424
61103124450254052221
734164406160306326
oct3322317772362725
9521831233777534
10120012122219989
113526a94531353a
12115631a0aaa071
1351c712c9b49cc
14218c890dc444d
15dd1bcd9b9694
hex6d267fe9e5d5

120012122219989 has 2 divisors, whose sum is σ = 120012122219990. Its totient is φ = 120012122219988.

The previous prime is 120012122219987. The next prime is 120012122220013. The reversal of 120012122219989 is 989912221210021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68092747859889 + 51919374360100 = 8251833^2 + 7205510^2 .

It is a cyclic number.

It is not a de Polignac number, because 120012122219989 - 21 = 120012122219987 is a prime.

It is a super-2 number, since 2×1200121222199892 (a number of 29 digits) contains 22 as substring.

Together with 120012122219987, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120012122219987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60006061109994 + 60006061109995.

It is an arithmetic number, because the mean of its divisors is an integer number (60006061109995).

Almost surely, 2120012122219989 is an apocalyptic number.

It is an amenable number.

120012122219989 is a deficient number, since it is larger than the sum of its proper divisors (1).

120012122219989 is an equidigital number, since it uses as much as digits as its factorization.

120012122219989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 186624, while the sum is 49.

The spelling of 120012122219989 in words is "one hundred twenty trillion, twelve billion, one hundred twenty-two million, two hundred nineteen thousand, nine hundred eighty-nine".