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1200121333207 is a prime number
BaseRepresentation
bin10001011101101100110…
…011100100010111010111
311020201201112000110211221
4101131230303210113113
5124130322030130312
62315154513111211
7152464061006116
oct21355463442727
94221645013757
101200121333207
11422a72229575
12174712258507
138922b78a6c4
144212c6adc7d
15213406a6207
hex1176cce45d7

1200121333207 has 2 divisors, whose sum is σ = 1200121333208. Its totient is φ = 1200121333206.

The previous prime is 1200121333141. The next prime is 1200121333217. The reversal of 1200121333207 is 7023331210021.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1200121333207 - 27 = 1200121333079 is a prime.

It is a super-4 number, since 4×12001213332074 (a number of 49 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200121333217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600060666603 + 600060666604.

It is an arithmetic number, because the mean of its divisors is an integer number (600060666604).

Almost surely, 21200121333207 is an apocalyptic number.

1200121333207 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200121333207 is an equidigital number, since it uses as much as digits as its factorization.

1200121333207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 1200121333207 its reverse (7023331210021), we get a palindrome (8223452543228).

The spelling of 1200121333207 in words is "one trillion, two hundred billion, one hundred twenty-one million, three hundred thirty-three thousand, two hundred seven".