Base | Representation |
---|---|
bin | 10001011101101100110… |
… | …011100100010111010111 |
3 | 11020201201112000110211221 |
4 | 101131230303210113113 |
5 | 124130322030130312 |
6 | 2315154513111211 |
7 | 152464061006116 |
oct | 21355463442727 |
9 | 4221645013757 |
10 | 1200121333207 |
11 | 422a72229575 |
12 | 174712258507 |
13 | 8922b78a6c4 |
14 | 4212c6adc7d |
15 | 213406a6207 |
hex | 1176cce45d7 |
1200121333207 has 2 divisors, whose sum is σ = 1200121333208. Its totient is φ = 1200121333206.
The previous prime is 1200121333141. The next prime is 1200121333217. The reversal of 1200121333207 is 7023331210021.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1200121333207 - 27 = 1200121333079 is a prime.
It is a super-4 number, since 4×12001213332074 (a number of 49 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1200121333217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600060666603 + 600060666604.
It is an arithmetic number, because the mean of its divisors is an integer number (600060666604).
Almost surely, 21200121333207 is an apocalyptic number.
1200121333207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200121333207 is an equidigital number, since it uses as much as digits as its factorization.
1200121333207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 1200121333207 its reverse (7023331210021), we get a palindrome (8223452543228).
The spelling of 1200121333207 in words is "one trillion, two hundred billion, one hundred twenty-one million, three hundred thirty-three thousand, two hundred seven".
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