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120013003131000 = 23353719643467783
BaseRepresentation
bin11011010010011010110100…
…011010111000100001111000
3120201221010112112110112022220
4123102122310122320201320
5111212243112300143000
61103125113523044040
734164440045032110
oct3322326432704170
9521833475415286
10120013003131000
1135270257597a71
12115633a7b10620
1351c7240356825
14218c935db2040
15dd1c30ec51a0
hex6d26b46b8878

120013003131000 has 512 divisors, whose sum is σ = 451156337049600. Its totient is φ = 25947306201600.

The previous prime is 120013003130899. The next prime is 120013003131001. The reversal of 120013003131000 is 131300310021.

It is a super-2 number, since 2×1200130031310002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120013003131001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 256323109 + ... + 256790891.

It is an arithmetic number, because the mean of its divisors is an integer number (881164720800).

Almost surely, 2120013003131000 is an apocalyptic number.

120013003131000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120013003131000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (225578168524800).

120013003131000 is an abundant number, since it is smaller than the sum of its proper divisors (331143333918600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120013003131000 is a wasteful number, since it uses less digits than its factorization.

120013003131000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 468476 (or 468462 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 120013003131000 its reverse (131300310021), we get a palindrome (120144303441021).

The spelling of 120013003131000 in words is "one hundred twenty trillion, thirteen billion, three million, one hundred thirty-one thousand".