Base | Representation |
---|---|
bin | 11011010010011011000000… |
… | …111011111011101011000101 |
3 | 120201221011002011121010202111 |
4 | 123102123000323323223011 |
5 | 111212244030024334341 |
6 | 1103125150423541021 |
7 | 34164445204645360 |
oct | 3322330073735305 |
9 | 521834064533674 |
10 | 120013213121221 |
11 | 35270355083802 |
12 | 115634462ba771 |
13 | 51c72749cb0b4 |
14 | 218c955c350d7 |
15 | dd1c44654681 |
hex | 6d26c0efbac5 |
120013213121221 has 4 divisors (see below), whose sum is σ = 137157957852832. Its totient is φ = 102868468389612.
The previous prime is 120013213121141. The next prime is 120013213121317. The reversal of 120013213121221 is 122121312310021.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 120013213121221 - 217 = 120013212990149 is a prime.
It is a super-2 number, since 2×1200132131212212 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120013213121192 and 120013213121201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120013213121621) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8572372365795 + ... + 8572372365808.
It is an arithmetic number, because the mean of its divisors is an integer number (34289489463208).
Almost surely, 2120013213121221 is an apocalyptic number.
It is an amenable number.
120013213121221 is a deficient number, since it is larger than the sum of its proper divisors (17144744731611).
120013213121221 is an equidigital number, since it uses as much as digits as its factorization.
120013213121221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17144744731610.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 120013213121221 its reverse (122121312310021), we get a palindrome (242134525431242).
The spelling of 120013213121221 in words is "one hundred twenty trillion, thirteen billion, two hundred thirteen million, one hundred twenty-one thousand, two hundred twenty-one".
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