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12002011201319 is a prime number
BaseRepresentation
bin1010111010100110111110…
…0111010011111100100111
31120111101021210111201100012
42232221233213103330213
53033120104331420234
641305351533040435
72346055011646136
oct256515747237447
946441253451305
1012002011201319
11390802a482157
12141a0a132611b
13690a28289539
142d6c86b5191d
1515c2ee7970ce
hexaea6f9d3f27

12002011201319 has 2 divisors, whose sum is σ = 12002011201320. Its totient is φ = 12002011201318.

The previous prime is 12002011201261. The next prime is 12002011201321. The reversal of 12002011201319 is 91310211020021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12002011201319 - 236 = 11933291724583 is a prime.

It is a super-2 number, since 2×120020112013192 (a number of 27 digits) contains 22 as substring.

Together with 12002011201321, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12002011201294 and 12002011201303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12002011201399) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001005600659 + 6001005600660.

It is an arithmetic number, because the mean of its divisors is an integer number (6001005600660).

Almost surely, 212002011201319 is an apocalyptic number.

12002011201319 is a deficient number, since it is larger than the sum of its proper divisors (1).

12002011201319 is an equidigital number, since it uses as much as digits as its factorization.

12002011201319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 23.

The spelling of 12002011201319 in words is "twelve trillion, two billion, eleven million, two hundred one thousand, three hundred nineteen".