Base | Representation |
---|---|
bin | 1010111010101011000011… |
… | …0001100100111100101011 |
3 | 1120111111002222120112200202 |
4 | 2232222300301210330223 |
5 | 3033124324212131220 |
6 | 41310052224222415 |
7 | 2346124055042504 |
oct | 256526061447453 |
9 | 46444088515622 |
10 | 12003104411435 |
11 | 390854057a095 |
12 | 141a34746aa0b |
13 | 690b70900827 |
14 | 2d6d4c003bab |
15 | 15c36573b275 |
hex | aeab0c64f2b |
12003104411435 has 32 divisors (see below), whose sum is σ = 15183622177920. Its totient is φ = 9091146240000.
The previous prime is 12003104411411. The next prime is 12003104411453. The reversal of 12003104411435 is 53411440130021.
It is not a de Polignac number, because 12003104411435 - 222 = 12003100217131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12003104411398 and 12003104411407.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 36644885 + ... + 36970985.
It is an arithmetic number, because the mean of its divisors is an integer number (474488193060).
Almost surely, 212003104411435 is an apocalyptic number.
12003104411435 is a deficient number, since it is larger than the sum of its proper divisors (3180517766485).
12003104411435 is a wasteful number, since it uses less digits than its factorization.
12003104411435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 329399.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 12003104411435 its reverse (53411440130021), we get a palindrome (65414544541456).
The spelling of 12003104411435 in words is "twelve trillion, three billion, one hundred four million, four hundred eleven thousand, four hundred thirty-five".
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