Base | Representation |
---|---|
bin | 11011010010101011101011… |
… | …110111010111000100101000 |
3 | 120201222212021122202222101001 |
4 | 123102223223313113010220 |
5 | 111213042204440242300 |
6 | 1103141310541004344 |
7 | 34165650611134501 |
oct | 3322535367270450 |
9 | 521885248688331 |
10 | 120031113212200 |
11 | 35277a00227023 |
12 | 11566a00b536b4 |
13 | 51c8b6831a3c8 |
14 | 218d773295ba8 |
15 | dd2440d7516a |
hex | 6d2aebdd7128 |
120031113212200 has 48 divisors (see below), whose sum is σ = 285010047564480. Its totient is φ = 46990903892160.
The previous prime is 120031113212159. The next prime is 120031113212221. The reversal of 120031113212200 is 2212311130021.
It is a super-3 number, since 3×1200311132122003 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6384624282 + ... + 6384643081.
It is an arithmetic number, because the mean of its divisors is an integer number (5937709324260).
Almost surely, 2120031113212200 is an apocalyptic number.
120031113212200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
120031113212200 is an abundant number, since it is smaller than the sum of its proper divisors (164978934352280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120031113212200 is a wasteful number, since it uses less digits than its factorization.
120031113212200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12769267426 (or 12769267417 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 120031113212200 its reverse (2212311130021), we get a palindrome (122243424342221).
The spelling of 120031113212200 in words is "one hundred twenty trillion, thirty-one billion, one hundred thirteen million, two hundred twelve thousand, two hundred".
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