| Base | Representation |
|---|---|
| bin | 1010111010101011000100… |
| … | …1110100100110100111000 |
| 3 | 1120111111010111212202020100 |
| 4 | 2232222301032210310320 |
| 5 | 3033124333133404422 |
| 6 | 41310053055155400 |
| 7 | 2346124206463023 |
| oct | 256526116446470 |
| 9 | 46444114782210 |
| 10 | 12003112013112 |
| 11 | 39085448a1370 |
| 12 | 141a349b15b60 |
| 13 | 690b7236286c |
| 14 | 2d6d4d0221ba |
| 15 | 15c36623d7ac |
| hex | aeab13a4d38 |
12003112013112 has 192 divisors, whose sum is σ = 37727812661760. Its totient is φ = 3407122252800.
The previous prime is 12003112013093. The next prime is 12003112013117. The reversal of 12003112013112 is 21131021130021.
12003112013112 is a `hidden beast` number, since 1 + 20 + 0 + 311 + 20 + 1 + 311 + 2 = 666.
12003112013112 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12003112013117) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 728353 + ... + 4953455.
It is an arithmetic number, because the mean of its divisors is an integer number (196499024280).
Almost surely, 212003112013112 is an apocalyptic number.
12003112013112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12003112013112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18863906330880).
12003112013112 is an abundant number, since it is smaller than the sum of its proper divisors (25724700648648).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12003112013112 is a wasteful number, since it uses less digits than its factorization.
12003112013112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4225354 (or 4225347 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 12003112013112 its reverse (21131021130021), we get a palindrome (33134133143133).
The spelling of 12003112013112 in words is "twelve trillion, three billion, one hundred twelve million, thirteen thousand, one hundred twelve".
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