Base | Representation |
---|---|
bin | 10110010110111001… |
… | …00101010000110111 |
3 | 1010222112010211210212 |
4 | 23023130211100313 |
5 | 144040304431403 |
6 | 5303022140035 |
7 | 603310351214 |
oct | 131334452067 |
9 | 33875124725 |
10 | 12003202103 |
11 | 50aa549442 |
12 | 23aba2161b |
13 | 1193a16169 |
14 | 81c212b0b |
15 | 4a3ba44d8 |
hex | 2cb725437 |
12003202103 has 4 divisors (see below), whose sum is σ = 12003812208. Its totient is φ = 12002592000.
The previous prime is 12003202091. The next prime is 12003202163. The reversal of 12003202103 is 30120230021.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30120230021 = 7 ⋅4302890003.
It is a cyclic number.
It is not a de Polignac number, because 12003202103 - 218 = 12002939959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12003202163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 274523 + ... + 315228.
It is an arithmetic number, because the mean of its divisors is an integer number (3000953052).
Almost surely, 212003202103 is an apocalyptic number.
12003202103 is a deficient number, since it is larger than the sum of its proper divisors (610105).
12003202103 is an equidigital number, since it uses as much as digits as its factorization.
12003202103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 610104.
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 12003202103 its reverse (30120230021), we get a palindrome (42123432124).
The spelling of 12003202103 in words is "twelve billion, three million, two hundred two thousand, one hundred three".
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