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12003310330011 = 327211132937179991
BaseRepresentation
bin1010111010101011110100…
…0011000110000010011011
31120111111122100001021212200
42232222331003012002123
53033130234421030021
641310124501541243
72346132135240300
oct256527503060233
946444570037780
1012003310330011
113908636834830
12141a3a4414823
13690ba447aa40
142d6d6b4c70a7
1515c378864126
hexaeabd0c609b

12003310330011 has 576 divisors, whose sum is σ = 25340578099200. Its totient is φ = 5371523942400.

The previous prime is 12003310329949. The next prime is 12003310330019. The reversal of 12003310330011 is 11003301330021.

It is a happy number.

12003310330011 is a `hidden beast` number, since 1 + 2 + 0 + 0 + 331 + 0 + 330 + 0 + 1 + 1 = 666.

12003310330011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 12003310330011 - 210 = 12003310328987 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12003310330019) by changing a digit.

It is a polite number, since it can be written in 575 ways as a sum of consecutive naturals, for example, 12112320726 + ... + 12112321716.

It is an arithmetic number, because the mean of its divisors is an integer number (43994059200).

Almost surely, 212003310330011 is an apocalyptic number.

12003310330011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

12003310330011 is an abundant number, since it is smaller than the sum of its proper divisors (13337267769189).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12003310330011 is a wasteful number, since it uses less digits than its factorization.

12003310330011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1280 (or 1270 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 12003310330011 its reverse (11003301330021), we get a palindrome (23006611660032).

It can be divided in two parts, 12003310 and 330011, that added together give a palindrome (12333321).

The spelling of 12003310330011 in words is "twelve trillion, three billion, three hundred ten million, three hundred thirty thousand, eleven".