Base | Representation |
---|---|
bin | 11011010010110110000111… |
… | …011001010111110001101010 |
3 | 120202000221012011021022200002 |
4 | 123102312013121113301222 |
5 | 111213233124001443200 |
6 | 1103150402125143002 |
7 | 34166525260600040 |
oct | 3322660731276152 |
9 | 522027164238602 |
10 | 120042312531050 |
11 | 35281727a22038 |
12 | 115690076baa62 |
13 | 51c9c31620cb0 |
14 | 219011680c390 |
15 | dd2899186bd5 |
hex | 6d2d87657c6a |
120042312531050 has 96 divisors (see below), whose sum is σ = 274809833961600. Its totient is φ = 37990683452160.
The previous prime is 120042312530977. The next prime is 120042312531079. The reversal of 120042312531050 is 50135213240021.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 267812021 + ... + 268259879.
It is an arithmetic number, because the mean of its divisors is an integer number (2862602437100).
Almost surely, 2120042312531050 is an apocalyptic number.
120042312531050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
120042312531050 is an abundant number, since it is smaller than the sum of its proper divisors (154767521430550).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120042312531050 is a wasteful number, since it uses less digits than its factorization.
120042312531050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 506800 (or 506795 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 120042312531050 its reverse (50135213240021), we get a palindrome (170177525771071).
The spelling of 120042312531050 in words is "one hundred twenty trillion, forty-two billion, three hundred twelve million, five hundred thirty-one thousand, fifty".
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