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120051210119 is a prime number
BaseRepresentation
bin110111111001110011…
…1000001011110000111
3102110212120112100120112
41233303213001132013
53431331102210434
6131052322023235
711446660310021
oct1576347013607
9373776470515
10120051210119
1146a05862035
121b324aa7b1b
13b4229a7509
145b4c077011
1531c971ddce
hex1bf39c1787

120051210119 has 2 divisors, whose sum is σ = 120051210120. Its totient is φ = 120051210118.

The previous prime is 120051210047. The next prime is 120051210121. The reversal of 120051210119 is 911012150021.

It is a strong prime.

It is an emirp because it is prime and its reverse (911012150021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120051210119 - 216 = 120051144583 is a prime.

It is a super-2 number, since 2×1200512101192 (a number of 23 digits) contains 22 as substring.

Together with 120051210121, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 120051210094 and 120051210103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120051210179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60025605059 + 60025605060.

It is an arithmetic number, because the mean of its divisors is an integer number (60025605060).

Almost surely, 2120051210119 is an apocalyptic number.

120051210119 is a deficient number, since it is larger than the sum of its proper divisors (1).

120051210119 is an equidigital number, since it uses as much as digits as its factorization.

120051210119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 23.

The spelling of 120051210119 in words is "one hundred twenty billion, fifty-one million, two hundred ten thousand, one hundred nineteen".