Base | Representation |
---|---|
bin | 1010111011000101001110… |
… | …0010000110111110100110 |
3 | 1120112011020121110221010211 |
4 | 2232301103202012332212 |
5 | 3033233221240310042 |
6 | 41313213315210034 |
7 | 2346463134456304 |
oct | 256612342067646 |
9 | 46464217427124 |
10 | 12010130010022 |
11 | 3910516318311 |
12 | 141b7882a691a |
13 | 6917202ca261 |
14 | 2d7417105274 |
15 | 15c627410017 |
hex | aec53886fa6 |
12010130010022 has 4 divisors (see below), whose sum is σ = 18015195015036. Its totient is φ = 6005065005010.
The previous prime is 12010130010013. The next prime is 12010130010059. The reversal of 12010130010022 is 22001003101021.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 12010130009984 and 12010130010011.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3002532502504 + ... + 3002532502507.
It is an arithmetic number, because the mean of its divisors is an integer number (4503798753759).
Almost surely, 212010130010022 is an apocalyptic number.
12010130010022 is a deficient number, since it is larger than the sum of its proper divisors (6005065005014).
12010130010022 is an equidigital number, since it uses as much as digits as its factorization.
12010130010022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6005065005013.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 12010130010022 its reverse (22001003101021), we get a palindrome (34011133111043).
The spelling of 12010130010022 in words is "twelve trillion, ten billion, one hundred thirty million, ten thousand, twenty-two".
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