Search a number
-
+
12010130010022 = 26005065005011
BaseRepresentation
bin1010111011000101001110…
…0010000110111110100110
31120112011020121110221010211
42232301103202012332212
53033233221240310042
641313213315210034
72346463134456304
oct256612342067646
946464217427124
1012010130010022
113910516318311
12141b7882a691a
136917202ca261
142d7417105274
1515c627410017
hexaec53886fa6

12010130010022 has 4 divisors (see below), whose sum is σ = 18015195015036. Its totient is φ = 6005065005010.

The previous prime is 12010130010013. The next prime is 12010130010059. The reversal of 12010130010022 is 22001003101021.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 12010130009984 and 12010130010011.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3002532502504 + ... + 3002532502507.

It is an arithmetic number, because the mean of its divisors is an integer number (4503798753759).

Almost surely, 212010130010022 is an apocalyptic number.

12010130010022 is a deficient number, since it is larger than the sum of its proper divisors (6005065005014).

12010130010022 is an equidigital number, since it uses as much as digits as its factorization.

12010130010022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6005065005013.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 12010130010022 its reverse (22001003101021), we get a palindrome (34011133111043).

The spelling of 12010130010022 in words is "twelve trillion, ten billion, one hundred thirty million, ten thousand, twenty-two".

Divisors: 1 2 6005065005011 12010130010022