Base | Representation |
---|---|
bin | 10110010111110100… |
… | …11001111110110101 |
3 | 1011000001212001020111 |
4 | 23023322121332311 |
5 | 144044310121323 |
6 | 5303501503021 |
7 | 603433662433 |
oct | 131372317665 |
9 | 34001761214 |
10 | 12011020213 |
11 | 51039a9295 |
12 | 23b2571a71 |
13 | 119552286a |
14 | 81d289d53 |
15 | 4a46eac0d |
hex | 2cbe99fb5 |
12011020213 has 2 divisors, whose sum is σ = 12011020214. Its totient is φ = 12011020212.
The previous prime is 12011020211. The next prime is 12011020237. The reversal of 12011020213 is 31202011021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11941681284 + 69338929 = 109278^2 + 8327^2 .
It is a cyclic number.
It is not a de Polignac number, because 12011020213 - 21 = 12011020211 is a prime.
Together with 12011020211, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 12011020193 and 12011020202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011020211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005510106 + 6005510107.
It is an arithmetic number, because the mean of its divisors is an integer number (6005510107).
Almost surely, 212011020213 is an apocalyptic number.
It is an amenable number.
12011020213 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011020213 is an equidigital number, since it uses as much as digits as its factorization.
12011020213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 12011020213 its reverse (31202011021), we get a palindrome (43213031234).
The spelling of 12011020213 in words is "twelve billion, eleven million, twenty thousand, two hundred thirteen".
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