Base | Representation |
---|---|
bin | 110111111011100101… |
… | …1000111000110100111 |
3 | 102111000202001002122111 |
4 | 1233313023013012213 |
5 | 3431441404031043 |
6 | 131102255341451 |
7 | 11451314446315 |
oct | 1576713070647 |
9 | 374022032574 |
10 | 120111002023 |
11 | 46a36590631 |
12 | 1b340b21887 |
13 | b4321b083c |
14 | 5b55d9d0b5 |
15 | 31cead009d |
hex | 1bf72c71a7 |
120111002023 has 2 divisors, whose sum is σ = 120111002024. Its totient is φ = 120111002022.
The previous prime is 120111002009. The next prime is 120111002047. The reversal of 120111002023 is 320200111021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120111002023 - 25 = 120111001991 is a prime.
It is a super-2 number, since 2×1201110020232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120111001994 and 120111002012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120111002923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60055501011 + 60055501012.
It is an arithmetic number, because the mean of its divisors is an integer number (60055501012).
Almost surely, 2120111002023 is an apocalyptic number.
120111002023 is a deficient number, since it is larger than the sum of its proper divisors (1).
120111002023 is an equidigital number, since it uses as much as digits as its factorization.
120111002023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 120111002023 its reverse (320200111021), we get a palindrome (440311113044).
The spelling of 120111002023 in words is "one hundred twenty billion, one hundred eleven million, two thousand, twenty-three".
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