Search a number
-
+
120111331110 = 2354393109559
BaseRepresentation
bin110111111011100110…
…0010111011100100110
3102111000202122211001220
41233313030113130212
53431442000043420
6131102310401210
711451320316621
oct1576714273446
9374022584056
10120111331110
1146a36795901
121b341060206
13b432297574
145b56046db8
1531ceb47840
hex1bf7317726

120111331110 has 32 divisors (see below), whose sum is σ = 294971086080. Its totient is φ = 31284811488.

The previous prime is 120111331103. The next prime is 120111331111. The reversal of 120111331110 is 11133111021.

120111331110 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1201113311102 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 120111331110.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120111331111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46553490 + ... + 46556069.

It is an arithmetic number, because the mean of its divisors is an integer number (9217846440).

Almost surely, 2120111331110 is an apocalyptic number.

120111331110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

120111331110 is an abundant number, since it is smaller than the sum of its proper divisors (174859754970).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120111331110 is a wasteful number, since it uses less digits than its factorization.

120111331110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93109612.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 120111331110 its reverse (11133111021), we get a palindrome (131244442131).

The spelling of 120111331110 in words is "one hundred twenty billion, one hundred eleven million, three hundred thirty-one thousand, one hundred ten".

Divisors: 1 2 3 5 6 10 15 30 43 86 129 215 258 430 645 1290 93109559 186219118 279328677 465547795 558657354 931095590 1396643385 2793286770 4003711037 8007422074 12011133111 20018555185 24022266222 40037110370 60055665555 120111331110