Base | Representation |
---|---|
bin | 11011010011111110011110… |
… | …000000001100110111001111 |
3 | 120202022100201102020122000211 |
4 | 123103332132000030313033 |
5 | 111221021230303020142 |
6 | 1103250211115303251 |
7 | 34205245415550433 |
oct | 3323763600146717 |
9 | 522270642218024 |
10 | 120120001220047 |
11 | 35301674191a34 |
12 | 1158008944ab27 |
13 | 520436295045a |
14 | 2193ba66129c3 |
15 | dd48e479c917 |
hex | 6d3f9e00cdcf |
120120001220047 has 2 divisors, whose sum is σ = 120120001220048. Its totient is φ = 120120001220046.
The previous prime is 120120001219979. The next prime is 120120001220101. The reversal of 120120001220047 is 740022100021021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120120001220047 - 27 = 120120001219919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120120001520047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060000610023 + 60060000610024.
It is an arithmetic number, because the mean of its divisors is an integer number (60060000610024).
Almost surely, 2120120001220047 is an apocalyptic number.
120120001220047 is a deficient number, since it is larger than the sum of its proper divisors (1).
120120001220047 is an equidigital number, since it uses as much as digits as its factorization.
120120001220047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 22.
Adding to 120120001220047 its reverse (740022100021021), we get a palindrome (860142101241068).
The spelling of 120120001220047 in words is "one hundred twenty trillion, one hundred twenty billion, one million, two hundred twenty thousand, forty-seven".
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