1201210023113 has 4 divisors (see below), whose sum is σ = 1239958733568. Its totient is φ = 1162461312660.

The previous prime is 1201210023077. The next prime is 1201210023119. The reversal of 1201210023113 is 3113200121021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1201210023113 - 2²⁴ = 1201193245897 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1201210023091 and 1201210023100.

It is not an unprimeable number, because it can be changed into a prime (1201210023119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19374355181 + ... + 19374355242.

It is an arithmetic number, because the mean of its divisors is an integer number (309989683392).

Almost surely, 2^{1201210023113} is an apocalyptic number.

It is an amenable number.

1201210023113 is a deficient number, since it is larger than the sum of its proper divisors (38748710455).

1201210023113 is an equidigital number, since it uses as much as digits as its factorization.

1201210023113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38748710454.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1201210023113 its reverse (3113200121021), we get a palindrome (4314410144134).

The spelling of 1201210023113 in words is "one trillion, two hundred one billion, two hundred ten million, twenty-three thousand, one hundred thirteen".