1201210023119 has 2 divisors, whose sum is σ = 1201210023120. Its totient is φ = 1201210023118.

The previous prime is 1201210023077. The next prime is 1201210023121. The reversal of 1201210023119 is 9113200121021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1201210023119 - 2¹⁶ = 1201209957583 is a prime.

It is a super-2 number, since 2×1201210023119² (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 1201210023121, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201210023094 and 1201210023103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201210023019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600605011559 + 600605011560.

It is an arithmetic number, because the mean of its divisors is an integer number (600605011560).

Almost surely, 2^{1201210023119} is an apocalyptic number.

1201210023119 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201210023119 is an equidigital number, since it uses as much as digits as its factorization.

1201210023119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 23.

The spelling of 1201210023119 in words is "one trillion, two hundred one billion, two hundred ten million, twenty-three thousand, one hundred nineteen".