Base | Representation |
---|---|
bin | 1010111011001100100110… |
… | …0100010110101100111011 |
3 | 1120112100100121202121021222 |
4 | 2232303021210112230323 |
5 | 3033301300214411303 |
6 | 41314142020022255 |
7 | 2346563201652233 |
oct | 256631144265473 |
9 | 46470317677258 |
10 | 12012110310203 |
11 | 391134212a133 |
12 | 142003b53198b |
13 | 691977667a03 |
14 | 2d7564112cc3 |
15 | 15c6e11d0938 |
hex | aecc9916b3b |
12012110310203 has 4 divisors (see below), whose sum is σ = 12534375975888. Its totient is φ = 11489844644520.
The previous prime is 12012110310173. The next prime is 12012110310301. The reversal of 12012110310203 is 30201301121021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12012110310203 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12012110310503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261132832808 + ... + 261132832853.
It is an arithmetic number, because the mean of its divisors is an integer number (3133593993972).
Almost surely, 212012110310203 is an apocalyptic number.
12012110310203 is a deficient number, since it is larger than the sum of its proper divisors (522265665685).
12012110310203 is an equidigital number, since it uses as much as digits as its factorization.
12012110310203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 522265665684.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 12012110310203 its reverse (30201301121021), we get a palindrome (42213411431224).
The spelling of 12012110310203 in words is "twelve trillion, twelve billion, one hundred ten million, three hundred ten thousand, two hundred three".
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