Base | Representation |
---|---|
bin | 11011010011111111100001… |
… | …011011000000110100111111 |
3 | 120202022110122020121120100212 |
4 | 123103333201123000310333 |
5 | 111221031034333301421 |
6 | 1103250515242543035 |
7 | 34205315432012204 |
oct | 3323774133006477 |
9 | 522273566546325 |
10 | 120121132322111 |
11 | 353020a470a728 |
12 | 11580344207a7b |
13 | 52044b30a090b |
14 | 2193c72929cab |
15 | dd495dc28e5b |
hex | 6d3fe16c0d3f |
120121132322111 has 2 divisors, whose sum is σ = 120121132322112. Its totient is φ = 120121132322110.
The previous prime is 120121132322101. The next prime is 120121132322143. The reversal of 120121132322111 is 111223231121021.
It is a weak prime.
It is an emirp because it is prime and its reverse (111223231121021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120121132322111 is a prime.
It is a super-2 number, since 2×1201211323221112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120121132322101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060566161055 + 60060566161056.
It is an arithmetic number, because the mean of its divisors is an integer number (60060566161056).
Almost surely, 2120121132322111 is an apocalyptic number.
120121132322111 is a deficient number, since it is larger than the sum of its proper divisors (1).
120121132322111 is an equidigital number, since it uses as much as digits as its factorization.
120121132322111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 23.
Adding to 120121132322111 its reverse (111223231121021), we get a palindrome (231344363443132).
The spelling of 120121132322111 in words is "one hundred twenty trillion, one hundred twenty-one billion, one hundred thirty-two million, three hundred twenty-two thousand, one hundred eleven".
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