Base | Representation |
---|---|
bin | 1010111011001101001111… |
… | …0100010100101000101111 |
3 | 1120112100210121022222022221 |
4 | 2232303103310110220233 |
5 | 3033302123230040312 |
6 | 41314211041420211 |
7 | 2346600360404434 |
oct | 256632364245057 |
9 | 46470717288287 |
10 | 12012282268207 |
11 | 39114201a9791 |
12 | 142008903a667 |
13 | 6919a4184300 |
14 | 2d757ccb5b8b |
15 | 15c70134b207 |
hex | aecd3d14a2f |
12012282268207 has 6 divisors (see below), whose sum is σ = 13007382574632. Its totient is φ = 11088260555112.
The previous prime is 12012282268187. The next prime is 12012282268229. The reversal of 12012282268207 is 70286228221021.
It is a happy number.
It is not a de Polignac number, because 12012282268207 - 215 = 12012282235439 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12012282268247) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 35539296483 + ... + 35539296820.
It is an arithmetic number, because the mean of its divisors is an integer number (2167897095772).
Almost surely, 212012282268207 is an apocalyptic number.
12012282268207 is a deficient number, since it is larger than the sum of its proper divisors (995100306425).
12012282268207 is an equidigital number, since it uses as much as digits as its factorization.
12012282268207 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71078593329 (or 71078593316 counting only the distinct ones).
The product of its (nonzero) digits is 172032, while the sum is 43.
The spelling of 12012282268207 in words is "twelve trillion, twelve billion, two hundred eighty-two million, two hundred sixty-eight thousand, two hundred seven".
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