1201230120113 has 2 divisors, whose sum is σ = 1201230120114. Its totient is φ = 1201230120112.

The previous prime is 1201230120107. The next prime is 1201230120173. The reversal of 1201230120113 is 3110210321021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1200225420304 + 1004699809 = 1095548^2 + 31697^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201230120113 - 2²⁴ = 1201213342897 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201230120091 and 1201230120100.

It is not a weakly prime, because it can be changed into another prime (1201230120173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600615060056 + 600615060057.

It is an arithmetic number, because the mean of its divisors is an integer number (600615060057).

Almost surely, 2^{1201230120113} is an apocalyptic number.

It is an amenable number.

1201230120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201230120113 is an equidigital number, since it uses as much as digits as its factorization.

1201230120113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1201230120113 its reverse (3110210321021), we get a palindrome (4311440441134).

The spelling of 1201230120113 in words is "one trillion, two hundred one billion, two hundred thirty million, one hundred twenty thousand, one hundred thirteen".