1201230120173 has 2 divisors, whose sum is σ = 1201230120174. Its totient is φ = 1201230120172.

The previous prime is 1201230120113. The next prime is 1201230120191. The reversal of 1201230120173 is 3710210321021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 614133966889 + 587096153284 = 783667^2 + 766222^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201230120173 - 2¹⁴ = 1201230103789 is a prime.

It is a super-2 number, since 2×1201230120173² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201230120113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600615060086 + 600615060087.

It is an arithmetic number, because the mean of its divisors is an integer number (600615060087).

Almost surely, 2^{1201230120173} is an apocalyptic number.

It is an amenable number.

1201230120173 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201230120173 is an equidigital number, since it uses as much as digits as its factorization.

1201230120173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 1201230120173 its reverse (3710210321021), we get a palindrome (4911440441194).

The spelling of 1201230120173 in words is "one trillion, two hundred one billion, two hundred thirty million, one hundred twenty thousand, one hundred seventy-three".