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120125629565317 is a prime number
BaseRepresentation
bin11011010100000011101101…
…011110101000100110000101
3120202022220020122222012021001
4123110003231132220212011
5111221114242132042232
61103252541414253301
734205535040651345
oct3324035536504605
9522286218865231
10120125629565317
1135303aa2248052
121158119a357231
135204a4ba2067c
14219417bd18d25
15dd4b239706e7
hex6d40ed7a8985

120125629565317 has 2 divisors, whose sum is σ = 120125629565318. Its totient is φ = 120125629565316.

The previous prime is 120125629565269. The next prime is 120125629565323. The reversal of 120125629565317 is 713565926521021.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106773906257316 + 13351723308001 = 10333146^2 + 3654001^2 .

It is a cyclic number.

It is not a de Polignac number, because 120125629565317 - 215 = 120125629532549 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120125629565017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60062814782658 + 60062814782659.

It is an arithmetic number, because the mean of its divisors is an integer number (60062814782659).

Almost surely, 2120125629565317 is an apocalyptic number.

It is an amenable number.

120125629565317 is a deficient number, since it is larger than the sum of its proper divisors (1).

120125629565317 is an equidigital number, since it uses as much as digits as its factorization.

120125629565317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6804000, while the sum is 55.

The spelling of 120125629565317 in words is "one hundred twenty trillion, one hundred twenty-five billion, six hundred twenty-nine million, five hundred sixty-five thousand, three hundred seventeen".