12013021012013 has 4 divisors (see below), whose sum is σ = 13729166870880. Its totient is φ = 10296875153148.

The previous prime is 12013021012007. The next prime is 12013021012021. The reversal of 12013021012013 is 31021012031021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12013021012013 - 2¹⁸ = 12013020749869 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12013021011982 and 12013021012000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013021012063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 858072929423 + ... + 858072929436.

It is an arithmetic number, because the mean of its divisors is an integer number (3432291717720).

Almost surely, 2^{12013021012013} is an apocalyptic number.

It is an amenable number.

12013021012013 is a deficient number, since it is larger than the sum of its proper divisors (1716145858867).

12013021012013 is an equidigital number, since it uses as much as digits as its factorization.

12013021012013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1716145858866.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12013021012013 its reverse (31021012031021), we get a palindrome (43034033043034).

The spelling of 12013021012013 in words is "twelve trillion, thirteen billion, twenty-one million, twelve thousand, thirteen".