Base | Representation |
---|---|
bin | 100011110011010… |
… | …0111000111001011 |
3 | 10002201110120022011 |
4 | 1013212213013023 |
5 | 4430013212021 |
6 | 315112040351 |
7 | 41524626025 |
oct | 10746470713 |
9 | 3081416264 |
10 | 1201304011 |
11 | 567117536 |
12 | 2963930b7 |
13 | 161b5cb9b |
14 | b578d015 |
15 | 706e6de1 |
hex | 479a71cb |
1201304011 has 2 divisors, whose sum is σ = 1201304012. Its totient is φ = 1201304010.
The previous prime is 1201304009. The next prime is 1201304023. The reversal of 1201304011 is 1104031021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1201304011 - 21 = 1201304009 is a prime.
Together with 1201304009, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1201303982 and 1201304000.
It is not a weakly prime, because it can be changed into another prime (1201304081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600652005 + 600652006.
It is an arithmetic number, because the mean of its divisors is an integer number (600652006).
Almost surely, 21201304011 is an apocalyptic number.
1201304011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201304011 is an equidigital number, since it uses as much as digits as its factorization.
1201304011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 1201304011 is about 34659.8328184081. The cubic root of 1201304011 is about 1063.0433516337.
Adding to 1201304011 its reverse (1104031021), we get a palindrome (2305335032).
The spelling of 1201304011 in words is "one billion, two hundred one million, three hundred four thousand, eleven".
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