Base | Representation |
---|---|
bin | 1010111011010000010010… |
… | …0011110011000101000000 |
3 | 1120112102220121002001221120 |
4 | 2232310010203303011000 |
5 | 3033310312101120112 |
6 | 41314424132552240 |
7 | 2346626550234516 |
oct | 256640443630500 |
9 | 46472817061846 |
10 | 12013100020032 |
11 | 39117aa864841 |
12 | 1420276a82680 |
13 | 691aa4711227 |
14 | 2d76197424b6 |
15 | 15c74d02ce8c |
hex | aed048f3140 |
12013100020032 has 56 divisors (see below), whose sum is σ = 31785026266752. Its totient is φ = 4004320588800.
The previous prime is 12013100020027. The next prime is 12013100020043. The reversal of 12013100020032 is 23002000131021.
It is a junction number, because it is equal to n+sod(n) for n = 12013100019993 and 12013100020020.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19098057 + ... + 19717047.
Almost surely, 212013100020032 is an apocalyptic number.
12013100020032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12013100020032 is an abundant number, since it is smaller than the sum of its proper divisors (19771926246720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12013100020032 is a wasteful number, since it uses less digits than its factorization.
12013100020032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 720087 (or 720077 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 12013100020032 its reverse (23002000131021), we get a palindrome (35015100151053).
The spelling of 12013100020032 in words is "twelve trillion, thirteen billion, one hundred million, twenty thousand, thirty-two".
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