12013102110001 has 2 divisors, whose sum is σ = 12013102110002. Its totient is φ = 12013102110000.

The previous prime is 12013102109999. The next prime is 12013102110013. The reversal of 12013102110001 is 10001120131021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11984052316401 + 29049793600 = 3461799^2 + 170440^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013102110001 - 2¹ = 12013102109999 is a prime.

Together with 12013102109999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (12013102110041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006551055000 + 6006551055001.

It is an arithmetic number, because the mean of its divisors is an integer number (6006551055001).

Almost surely, 2^{12013102110001} is an apocalyptic number.

It is an amenable number.

12013102110001 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013102110001 is an equidigital number, since it uses as much as digits as its factorization.

12013102110001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 12013102110001 its reverse (10001120131021), we get a palindrome (22014222241022).

It can be divided in two parts, 120131021 and 10001, that multiplied together give a palindrome (1201430341021).

The spelling of 12013102110001 in words is "twelve trillion, thirteen billion, one hundred two million, one hundred ten thousand, one".