12013102201111 has 4 divisors (see below), whose sum is σ = 13105202401224. Its totient is φ = 10921002001000.

The previous prime is 12013102201097. The next prime is 12013102201127. The reversal of 12013102201111 is 11110220131021.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12013102201111 - 2¹⁵ = 12013102168343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013102201171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 546050100040 + ... + 546050100061.

It is an arithmetic number, because the mean of its divisors is an integer number (3276300600306).

Almost surely, 2^{12013102201111} is an apocalyptic number.

12013102201111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

12013102201111 is a deficient number, since it is larger than the sum of its proper divisors (1092100200113).

12013102201111 is a wasteful number, since it uses less digits than its factorization.

12013102201111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1092100200112.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 12013102201111 its reverse (11110220131021), we get a palindrome (23123322332132).

The spelling of 12013102201111 in words is "twelve trillion, thirteen billion, one hundred two million, two hundred one thousand, one hundred eleven".