Base | Representation |
---|---|
bin | 10001011110110011101… |
… | …011001100101001001111 |
3 | 11020211210101022022210102 |
4 | 101132303223030221033 |
5 | 124140240420234411 |
6 | 2315512505201315 |
7 | 152535406151366 |
oct | 21366353145117 |
9 | 4224711268712 |
10 | 1201310321231 |
11 | 4235223a38a9 |
12 | 1749a449023b |
13 | 8938abc7807 |
14 | 422025747dd |
15 | 213aec68d3b |
hex | 117b3acca4f |
1201310321231 has 2 divisors, whose sum is σ = 1201310321232. Its totient is φ = 1201310321230.
The previous prime is 1201310321227. The next prime is 1201310321249. The reversal of 1201310321231 is 1321230131021.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1201310321231 - 22 = 1201310321227 is a prime.
It is a super-2 number, since 2×12013103212312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201310321201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600655160615 + 600655160616.
It is an arithmetic number, because the mean of its divisors is an integer number (600655160616).
Almost surely, 21201310321231 is an apocalyptic number.
1201310321231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201310321231 is an equidigital number, since it uses as much as digits as its factorization.
1201310321231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1201310321231 its reverse (1321230131021), we get a palindrome (2522540452252).
The spelling of 1201310321231 in words is "one trillion, two hundred one billion, three hundred ten million, three hundred twenty-one thousand, two hundred thirty-one".
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