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12013121312220 = 223571991213118493
BaseRepresentation
bin1010111011010000010111…
…0101000001010111011100
31120112102222002010211100010
42232310011311001113130
53033310333023442340
641314430213203220
72346630226225050
oct256640565012734
946472862124303
1012013121312220
113911810887996
121420282030510
13691aa8c57862
142d761c4c5c60
1515c74ed36b80
hexaed05d415dc

12013121312220 has 192 divisors, whose sum is σ = 38667341260800. Its totient is φ = 2729782674432.

The previous prime is 12013121312197. The next prime is 12013121312243. The reversal of 12013121312220 is 2221312131021.

12013121312220 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (12013121312197) and next prime (12013121312243).

It is a super-2 number, since 2×120131213122202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 101323294 + ... + 101441786.

It is an arithmetic number, because the mean of its divisors is an integer number (201392402400).

Almost surely, 212013121312220 is an apocalyptic number.

12013121312220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12013121312220, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19333670630400).

12013121312220 is an abundant number, since it is smaller than the sum of its proper divisors (26654219948580).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12013121312220 is a wasteful number, since it uses less digits than its factorization.

12013121312220 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119924 (or 119922 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 12013121312220 its reverse (2221312131021), we get a palindrome (14234433443241).

The spelling of 12013121312220 in words is "twelve trillion, thirteen billion, one hundred twenty-one million, three hundred twelve thousand, two hundred twenty".