12013130219 has 2 divisors, whose sum is σ = 12013130220. Its totient is φ = 12013130218.

The previous prime is 12013130179. The next prime is 12013130237. The reversal of 12013130219 is 91203131021.

12013130219 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12013130219 - 2¹² = 12013126123 is a prime.

It is a super-2 number, since 2×12013130219² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12013130194 and 12013130203.

It is not a weakly prime, because it can be changed into another prime (12013135219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006565109 + 6006565110.

It is an arithmetic number, because the mean of its divisors is an integer number (6006565110).

Almost surely, 2^12013130219 is an apocalyptic number.

12013130219 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013130219 is an equidigital number, since it uses as much as digits as its factorization.

12013130219 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 23.

The spelling of 12013130219 in words is "twelve billion, thirteen million, one hundred thirty thousand, two hundred nineteen".