12013134101 has 4 divisors (see below), whose sum is σ = 12047754432. Its totient is φ = 11978513772.

The previous prime is 12013133983. The next prime is 12013134139. The reversal of 12013134101 is 10143131021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12013134101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12013134101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013134181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17309645 + ... + 17310338.

It is an arithmetic number, because the mean of its divisors is an integer number (3011938608).

Almost surely, 2^12013134101 is an apocalyptic number.

It is an amenable number.

12013134101 is a deficient number, since it is larger than the sum of its proper divisors (34620331).

12013134101 is an equidigital number, since it uses as much as digits as its factorization.

12013134101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34620330.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12013134101 its reverse (10143131021), we get a palindrome (22156265122).

The spelling of 12013134101 in words is "twelve billion, thirteen million, one hundred thirty-four thousand, one hundred one".