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1201320001200 = 2435211233956917
BaseRepresentation
bin10001011110110100010…
…000000111111010110000
311020211211001112010012210
4101132310100013322300
5124140300410014300
62315513452452120
7152535554346024
oct21366420077260
94224731463183
101201320001200
11423527905580
121749a777a040
138938cc067c7
1442203974384
15213b0a2c050
hex117b4407eb0

1201320001200 has 240 divisors, whose sum is σ = 4380593124096. Its totient is φ = 278566886400.

The previous prime is 1201320001199. The next prime is 1201320001237. The reversal of 1201320001200 is 21000231021.

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1674859 + ... + 2282058.

Almost surely, 21201320001200 is an apocalyptic number.

1201320001200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1201320001200 is an abundant number, since it is smaller than the sum of its proper divisors (3179273122896).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1201320001200 is a wasteful number, since it uses less digits than its factorization.

1201320001200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3956972 (or 3956961 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 1201320001200 its reverse (21000231021), we get a palindrome (1222320232221).

The spelling of 1201320001200 in words is "one trillion, two hundred one billion, three hundred twenty million, one thousand, two hundred".