12013202011 has 2 divisors, whose sum is σ = 12013202012. Its totient is φ = 12013202010.

The previous prime is 12013201969. The next prime is 12013202027. The reversal of 12013202011 is 11020231021.

12013202011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12013202011 - 2¹⁷ = 12013070939 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12013201982 and 12013202000.

It is not a weakly prime, because it can be changed into another prime (12013202051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006601005 + 6006601006.

It is an arithmetic number, because the mean of its divisors is an integer number (6006601006).

Almost surely, 2^12013202011 is an apocalyptic number.

12013202011 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013202011 is an equidigital number, since it uses as much as digits as its factorization.

12013202011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 12013202011 its reverse (11020231021), we get a palindrome (23033433032).

The spelling of 12013202011 in words is "twelve billion, thirteen million, two hundred two thousand, eleven".