Base | Representation |
---|---|
bin | 10110011000000101… |
… | …01110101010000011 |
3 | 1011000012221220011022 |
4 | 23030002232222003 |
5 | 144100334431201 |
6 | 5304020340055 |
7 | 603461350454 |
oct | 131402565203 |
9 | 34005856138 |
10 | 12013202051 |
11 | 5105159564 |
12 | 23b324462b |
13 | 1195b079a6 |
14 | 81d69712b |
15 | 4a49cc41b |
hex | 2cc0aea83 |
12013202051 has 2 divisors, whose sum is σ = 12013202052. Its totient is φ = 12013202050.
The previous prime is 12013202039. The next prime is 12013202101. The reversal of 12013202051 is 15020231021.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (15020231021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12013202051 - 230 = 10939460227 is a prime.
It is not a weakly prime, because it can be changed into another prime (12013202011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006601025 + 6006601026.
It is an arithmetic number, because the mean of its divisors is an integer number (6006601026).
Almost surely, 212013202051 is an apocalyptic number.
12013202051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013202051 is an equidigital number, since it uses as much as digits as its factorization.
12013202051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 17.
Adding to 12013202051 its reverse (15020231021), we get a palindrome (27033433072).
The spelling of 12013202051 in words is "twelve billion, thirteen million, two hundred two thousand, fifty-one".
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