Base | Representation |
---|---|
bin | 110111111100001101… |
… | …1010010111101110011 |
3 | 102111002012121000211000 |
4 | 1233320123102331303 |
5 | 3432012244202011 |
6 | 131104330053043 |
7 | 11451661224402 |
oct | 1577033227563 |
9 | 374065530730 |
10 | 120132022131 |
11 | 46a47438320 |
12 | 1b347b7a183 |
13 | b436660384 |
14 | 5b58ab1639 |
15 | 31d1883356 |
hex | 1bf86d2f73 |
120132022131 has 128 divisors (see below), whose sum is σ = 207189964800. Its totient is φ = 68072209920.
The previous prime is 120132022111. The next prime is 120132022159. The reversal of 120132022131 is 131220231021.
120132022131 is a `hidden beast` number, since 120 + 1 + 320 + 221 + 3 + 1 = 666.
It is not a de Polignac number, because 120132022131 - 25 = 120132022099 is a prime.
It is a super-2 number, since 2×1201320221312 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (120132022111) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 140834301 + ... + 140835153.
It is an arithmetic number, because the mean of its divisors is an integer number (1618671600).
Almost surely, 2120132022131 is an apocalyptic number.
120132022131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
120132022131 is a deficient number, since it is larger than the sum of its proper divisors (87057942669).
120132022131 is a wasteful number, since it uses less digits than its factorization.
120132022131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1338 (or 1332 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 120132022131 its reverse (131220231021), we get a palindrome (251352253152).
The spelling of 120132022131 in words is "one hundred twenty billion, one hundred thirty-two million, twenty-two thousand, one hundred thirty-one".
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