Base | Representation |
---|---|
bin | 10001011110110100010… |
… | …100110111010111001111 |
3 | 11020211211010212021011112 |
4 | 101132310110313113033 |
5 | 124140301214302421 |
6 | 2315513535242235 |
7 | 152535601043462 |
oct | 21366424672717 |
9 | 4224733767145 |
10 | 1201321244111 |
11 | 42352858437a |
12 | 1749a807937b |
13 | 89390250461 |
14 | 42203bb92d9 |
15 | 213b0bc545b |
hex | 117b45375cf |
1201321244111 has 2 divisors, whose sum is σ = 1201321244112. Its totient is φ = 1201321244110.
The previous prime is 1201321244099. The next prime is 1201321244113. The reversal of 1201321244111 is 1114421231021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201321244111 is a prime.
Together with 1201321244113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201321244113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600660622055 + 600660622056.
It is an arithmetic number, because the mean of its divisors is an integer number (600660622056).
Almost surely, 21201321244111 is an apocalyptic number.
1201321244111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201321244111 is an equidigital number, since it uses as much as digits as its factorization.
1201321244111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 1201321244111 its reverse (1114421231021), we get a palindrome (2315742475132).
The spelling of 1201321244111 in words is "one trillion, two hundred one billion, three hundred twenty-one million, two hundred forty-four thousand, one hundred eleven".
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