12013241533 has 2 divisors, whose sum is σ = 12013241534. Its totient is φ = 12013241532.

The previous prime is 12013241521. The next prime is 12013241567. The reversal of 12013241533 is 33514231021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11432527929 + 580713604 = 106923^2 + 24098^2 .

It is an emirp because it is prime and its reverse (33514231021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12013241533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12013241498 and 12013241507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013241033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006620766 + 6006620767.

It is an arithmetic number, because the mean of its divisors is an integer number (6006620767).

Almost surely, 2^12013241533 is an apocalyptic number.

It is an amenable number.

12013241533 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013241533 is an equidigital number, since it uses as much as digits as its factorization.

12013241533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 12013241533 its reverse (33514231021), we get a palindrome (45527472554).

The spelling of 12013241533 in words is "twelve billion, thirteen million, two hundred forty-one thousand, five hundred thirty-three".