Base | Representation |
---|---|
bin | 10110011000000110… |
… | …01011011100010111 |
3 | 1011000020011212220021 |
4 | 23030003023130113 |
5 | 144100402214314 |
6 | 5304023050011 |
7 | 603462351304 |
oct | 131403133427 |
9 | 34006155807 |
10 | 12013319959 |
11 | 510522a103 |
12 | 23b32a0907 |
13 | 1195b49564 |
14 | 81d6c80ab |
15 | 4a4a02324 |
hex | 2cc0cb717 |
12013319959 has 2 divisors, whose sum is σ = 12013319960. Its totient is φ = 12013319958.
The previous prime is 12013319953. The next prime is 12013319993. The reversal of 12013319959 is 95991331021.
It is a happy number.
12013319959 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (95991331021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12013319959 - 213 = 12013311767 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12013319953) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006659979 + 6006659980.
It is an arithmetic number, because the mean of its divisors is an integer number (6006659980).
Almost surely, 212013319959 is an apocalyptic number.
12013319959 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013319959 is an equidigital number, since it uses as much as digits as its factorization.
12013319959 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 65610, while the sum is 43.
The spelling of 12013319959 in words is "twelve billion, thirteen million, three hundred nineteen thousand, nine hundred fifty-nine".
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