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1201333203230 = 25292142845803
BaseRepresentation
bin10001011110110101000…
…010011111000100011110
311020211211222100211222212
4101132311002133010132
5124140312300000410
62315515043440422
7152536104512636
oct21366502370436
94224758324885
101201333203230
11423534302446
121749b0086112
1389392879964
144220560d6c6
15213b1c88b05
hex117b509f11e

1201333203230 has 24 divisors (see below), whose sum is σ = 2239536515112. Its totient is φ = 463963164896.

The previous prime is 1201333203211. The next prime is 1201333203263. The reversal of 1201333203230 is 323023331021.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1201333203196 and 1201333203205.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 71414492 + ... + 71431311.

It is an arithmetic number, because the mean of its divisors is an integer number (93314021463).

Almost surely, 21201333203230 is an apocalyptic number.

1201333203230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1201333203230 is a deficient number, since it is larger than the sum of its proper divisors (1038203311882).

1201333203230 is a wasteful number, since it uses less digits than its factorization.

1201333203230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 142845868 (or 142845839 counting only the distinct ones).

The product of its (nonzero) digits is 1944, while the sum is 23.

Adding to 1201333203230 its reverse (323023331021), we get a palindrome (1524356534251).

The spelling of 1201333203230 in words is "one trillion, two hundred one billion, three hundred thirty-three million, two hundred three thousand, two hundred thirty".

Divisors: 1 2 5 10 29 58 145 290 841 1682 4205 8410 142845803 285691606 714229015 1428458030 4142528287 8285056574 20712641435 41425282870 120133320323 240266640646 600666601615 1201333203230