120134403020032 has 72 divisors (see below), whose sum is σ = 239957468150400. Its totient is φ = 60027649769472.

The previous prime is 120134403020029. The next prime is 120134403020129. The reversal of 120134403020032 is 230020304431021.

It is a super-3 number, since 3×120134403020032³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120134403019979 and 120134403020006.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4319968944 + ... + 4319996752.

It is an arithmetic number, because the mean of its divisors is an integer number (3332742613200).

Almost surely, 2^{120134403020032} is an apocalyptic number.

It is an amenable number.

120134403020032 is a deficient number, since it is larger than the sum of its proper divisors (119823065130368).

120134403020032 is an equidigital number, since it uses as much as digits as its factorization.

120134403020032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38331 (or 38317 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 120134403020032 its reverse (230020304431021), we get a palindrome (350154707451053).

The spelling of 120134403020032 in words is "one hundred twenty trillion, one hundred thirty-four billion, four hundred three million, twenty thousand, thirty-two".