Base | Representation |
---|---|
bin | 10001011110110101101… |
… | …101010100010011001110 |
3 | 11020211212202111022000200 |
4 | 101132311231110103032 |
5 | 124140323133300220 |
6 | 2315520124234330 |
7 | 152536302115602 |
oct | 21366555242316 |
9 | 4224782438020 |
10 | 1201344431310 |
11 | 42353a681251 |
12 | 1749b399b9a6 |
13 | 89394cab4aa |
14 | 42206cd3502 |
15 | 213b2c55890 |
hex | 117b5b544ce |
1201344431310 has 48 divisors (see below), whose sum is σ = 3139191525600. Its totient is φ = 318748668480.
The previous prime is 1201344431303. The next prime is 1201344431333. The reversal of 1201344431310 is 131344431021.
1201344431310 is a `hidden beast` number, since 1 + 2 + 0 + 1 + 344 + 4 + 3 + 1 + 310 = 666.
It is a super-2 number, since 2×12013444313102 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 33520461 + ... + 33556280.
It is an arithmetic number, because the mean of its divisors is an integer number (65399823450).
Almost surely, 21201344431310 is an apocalyptic number.
1201344431310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1201344431310 is an abundant number, since it is smaller than the sum of its proper divisors (1937847094290).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201344431310 is a wasteful number, since it uses less digits than its factorization.
1201344431310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67076953 (or 67076950 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 1201344431310 its reverse (131344431021), we get a palindrome (1332688862331).
The spelling of 1201344431310 in words is "one trillion, two hundred one billion, three hundred forty-four million, four hundred thirty-one thousand, three hundred ten".
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