Base | Representation |
---|---|
bin | 10110011000001000… |
… | …00111110110111111 |
3 | 1011000020122110100121 |
4 | 23030010013312333 |
5 | 144100433124143 |
6 | 5304032235411 |
7 | 603464431624 |
oct | 131404076677 |
9 | 34006573317 |
10 | 12013567423 |
11 | 5105389020 |
12 | 23b339bb67 |
13 | 1195c050a0 |
14 | 81d75034b |
15 | 4a4a507ed |
hex | 2cc107dbf |
12013567423 has 32 divisors (see below), whose sum is σ = 14594291712. Its totient is φ = 9739267200.
The previous prime is 12013567411. The next prime is 12013567439. The reversal of 12013567423 is 32476531021.
It is not a de Polignac number, because 12013567423 - 221 = 12011470271 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12013567453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2999140 + ... + 3003142.
It is an arithmetic number, because the mean of its divisors is an integer number (456071616).
Almost surely, 212013567423 is an apocalyptic number.
12013567423 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12013567423 is a deficient number, since it is larger than the sum of its proper divisors (2580724289).
12013567423 is a wasteful number, since it uses less digits than its factorization.
12013567423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4735.
The product of its (nonzero) digits is 30240, while the sum is 34.
The spelling of 12013567423 in words is "twelve billion, thirteen million, five hundred sixty-seven thousand, four hundred twenty-three".
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