Base | Representation |
---|---|
bin | 100011110011100… |
… | …0100001101111111 |
3 | 10002201200121211201 |
4 | 1013213010031333 |
5 | 4430031020411 |
6 | 315114400331 |
7 | 41525633431 |
oct | 10747041577 |
9 | 3081617751 |
10 | 1201423231 |
11 | 567199068 |
12 | 2964300a7 |
13 | 161ba2228 |
14 | b57c0651 |
15 | 7071c3c1 |
hex | 479c437f |
1201423231 has 4 divisors (see below), whose sum is σ = 1216631200. Its totient is φ = 1186215264.
The previous prime is 1201423211. The next prime is 1201423241. The reversal of 1201423231 is 1323241021.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1323241021 = 43 ⋅30773047.
It is a cyclic number.
It is not a de Polignac number, because 1201423231 - 25 = 1201423199 is a prime.
It is a super-5 number, since 5×12014232315 (a number of 47 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1201423199 and 1201423208.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201423211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7603866 + ... + 7604023.
It is an arithmetic number, because the mean of its divisors is an integer number (304157800).
Almost surely, 21201423231 is an apocalyptic number.
1201423231 is a deficient number, since it is larger than the sum of its proper divisors (15207969).
1201423231 is an equidigital number, since it uses as much as digits as its factorization.
1201423231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15207968.
The product of its (nonzero) digits is 288, while the sum is 19.
The square root of 1201423231 is about 34661.5526340065. The cubic root of 1201423231 is about 1063.0785167085.
Adding to 1201423231 its reverse (1323241021), we get a palindrome (2524664252).
It can be divided in two parts, 12014 and 23231, that added together give a triangular number (35245 = T265).
The spelling of 1201423231 in words is "one billion, two hundred one million, four hundred twenty-three thousand, two hundred thirty-one".
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