1201442111 has 2 divisors, whose sum is σ = 1201442112. Its totient is φ = 1201442110.

The previous prime is 1201442089. The next prime is 1201442113. The reversal of 1201442111 is 1112441021.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201442111 is a prime.

Together with 1201442113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1201442111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201442113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600721055 + 600721056.

It is an arithmetic number, because the mean of its divisors is an integer number (600721056).

Almost surely, 2^1201442111 is an apocalyptic number.

1201442111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201442111 is an equidigital number, since it uses as much as digits as its factorization.

1201442111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 17.

The square root of 1201442111 is about 34661.8249808056. The cubic root of 1201442111 is about 1063.0840853310.

Adding to 1201442111 its reverse (1112441021), we get a palindrome (2313883132).

The spelling of 1201442111 in words is "one billion, two hundred one million, four hundred forty-two thousand, one hundred eleven".