Base | Representation |
---|---|
bin | 10110011000111011… |
… | …10011111000000000 |
3 | 1011000201022120111220 |
4 | 23030131303320000 |
5 | 144104144120222 |
6 | 5304432435040 |
7 | 603605606145 |
oct | 131435637000 |
9 | 34021276456 |
10 | 12020301312 |
11 | 5109168318 |
12 | 23b56a8a80 |
13 | 1197422136 |
14 | 8205c43cc |
15 | 4a5430b5c |
hex | 2cc773e00 |
12020301312 has 40 divisors (see below), whose sum is σ = 32022838056. Its totient is φ = 4006766592.
The previous prime is 12020301311. The next prime is 12020301317. The reversal of 12020301312 is 21310302021.
It is a junction number, because it is equal to n+sod(n) for n = 12020301291 and 12020301300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12020301311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3911323 + ... + 3914394.
Almost surely, 212020301312 is an apocalyptic number.
12020301312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12020301312 is an abundant number, since it is smaller than the sum of its proper divisors (20002536744).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12020301312 is an frugal number, since it uses more digits than its factorization.
12020301312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7825738 (or 7825722 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 12020301312 its reverse (21310302021), we get a palindrome (33330603333).
The spelling of 12020301312 in words is "twelve billion, twenty million, three hundred one thousand, three hundred twelve".
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