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1202112102022 = 21346235080847
BaseRepresentation
bin10001011111100011011…
…101101111111010000110
311020220212021000000021021
4101133203131233322012
5124143411144231042
62320124230141354
7152564313162616
oct21374335577206
94226767000237
101202112102022
114238a3a40657
12174b88ab185a
1389488052110
144227ac44a46
152140a343867
hex117e376fe86

1202112102022 has 8 divisors (see below), whose sum is σ = 1941873395616. Its totient is φ = 554820970152.

The previous prime is 1202112102001. The next prime is 1202112102083. The reversal of 1202112102022 is 2202012112021.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1202112101987 and 1202112102005.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23117540398 + ... + 23117540449.

It is an arithmetic number, because the mean of its divisors is an integer number (242734174452).

Almost surely, 21202112102022 is an apocalyptic number.

1202112102022 is a deficient number, since it is larger than the sum of its proper divisors (739761293594).

1202112102022 is a wasteful number, since it uses less digits than its factorization.

1202112102022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46235080862.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 1202112102022 its reverse (2202012112021), we get a palindrome (3404124214043).

Subtracting 1202112102022 from its reverse (2202012112021), we obtain a palindrome (999900009999).

The spelling of 1202112102022 in words is "one trillion, two hundred two billion, one hundred twelve million, one hundred two thousand, twenty-two".

Divisors: 1 2 13 26 46235080847 92470161694 601056051011 1202112102022