1202201201231 has 2 divisors, whose sum is σ = 1202201201232. Its totient is φ = 1202201201230.

The previous prime is 1202201201203. The next prime is 1202201201233. The reversal of 1202201201231 is 1321021022021.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1202201201231 is a prime.

It is a super-2 number, since 2×1202201201231² (a number of 25 digits) contains 22 as substring.

Together with 1202201201233, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1202201201233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601100600615 + 601100600616.

It is an arithmetic number, because the mean of its divisors is an integer number (601100600616).

Almost surely, 2^{1202201201231} is an apocalyptic number.

1202201201231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202201201231 is an equidigital number, since it uses as much as digits as its factorization.

1202201201231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1202201201231 its reverse (1321021022021), we get a palindrome (2523222223252).

The spelling of 1202201201231 in words is "one trillion, two hundred two billion, two hundred one million, two hundred one thousand, two hundred thirty-one".